Question: 1.1 In a turning operation on stainless steel with hardness = 200 HB, the cutting speed = 200m/min, feed = 0.25mm/rev, and depth of cut = 7.5mm. How much power will the lathe draw in performing this operation if its mechanical efficiency = 90%. U= 2.8 J/mm3. [3] 1.2 A face milling operation is used to machine 5mm from the top surface of a rectangular piece

EngineeringMechanical EngineeringMechanical Engineering questions and answers1.1 In a turning operation on stainless steel with hardness =
200 HB, the cutting speed = 200m/min, feed = 0.25mm/rev, and depth
of cut = 7.5mm. How much power will the lathe draw in performing
this operation if its mechanical efficiency = 90%. U= 2.8 J/mm3.
[3]
1.2 A face milling operation is used to machine 5mm from the top
surface of a rectangular pieceQuestion: 1.1 In a turning operation on stainless steel with hardness =
200 HB, the cutting speed = 200m/min, feed = 0.25mm/rev, and depth
of cut = 7.5mm. How much power will the lathe draw in performing
this operation if its mechanical efficiency = 90%. U= 2.8 J/mm3.
[3]
1.2 A face milling operation is used to machine 5mm from the top
surface of a rectangular pieceThis question hasn’t been solved yetAsk an expertAsk an expertAsk an expert done loading1.1 In a turning operation on stainless steel with hardness =
200 HB, the cutting speed = 200m/min, feed = 0.25mm/rev, and depth
of cut = 7.5mm. How much power will the lathe draw in performing
this operation if its mechanical efficiency = 90%. U= 2.8 J/mm3.
[3]
1.2 A face milling operation is used to machine 5mm from the top
surface of a rectangular piece of aluminium 400mm long by 100mm
wide. The cutter has four teeth (cemented carbide inserts) and is
150mm in diameter. Cutting conditions are: v = 3m/s, f =
0.27mm/tooth, and d = 5.0mm. Determine:
1.2.1 time to make one pass across the surface, and
1.2.2 metal removal rate during cutting. [7]
1.3 The outside diameter of a cylinder made of a steel alloy is
to be turned. The starting diameter is 300 mm and the length is 625
mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut
will be made with a cemented carbide cutting tool whose Taylor tool
life parameters are: n = 0.24 and C = 450. Units for the Taylor
equation are min for tool life and m/min for cutting speed.
1.3.1 Compute the cutting speed that will allow the tool life to
be just equal to the cutting time for three of these parts.
[10]
1.4 The outside diameter of a cylinder made of titanium alloy is
to be turned. The starting diameter = 400 mm, and length = 1100 mm.
Feed = 0.35 mm/rev, and depth of cut = 2.5 mm. The cut will be made
with a cemented carbide tool whose Taylor tool life parameters are:
n = 0.24 and C = 450. Units for the Taylor equation are min for
tool life and m/min for cutting speed. Compute the cutting speed
that will allow the tool life to be 10% longer than the machining
time for this part.
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